if A+B+C=90° then prove that sinA+sinB+sinC=1+4(sin(90-2A)/4)(sin(90-2B)/4)(sin(90-2C)/4)​

if A+B+C=90° then prove that sinA+sinB+sinC=1+4(sin(90-2A)/4)(sin(90-2B)/4)(sin(90-2C)/4)​

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