factories the following algebraic expressions(a) ax+bx_ay_by give me the answer About the author Adalyn
Step-by-step explanation: Given :– ax+bx_ay_by To find:– Factorise the given expression Solution:– Method –1:– Given expression is ax + bx -ay -by =>(ax+bx)-(ay+by) =>(a+b)x -(a+b)y =>(a+b)(x-y) ax + bx -ay -by = (a+b)(x-y) Method-2:– Given expression is ax + bx -ay -by =>(ax-ay)+(bx-by) =>a(x-y)+b(x-y) =>(x-y)(a+b) ax + bx -ay -by = (a+b)(x-y) Answer:– The factorization of the given expression is ax + bx -ay -by = (a+b)(x-y) Reply
Step-by-step explanation:
Given :–
ax+bx_ay_by
To find:–
Factorise the given expression
Solution:–
Method –1:–
Given expression is ax + bx -ay -by
=>(ax+bx)-(ay+by)
=>(a+b)x -(a+b)y
=>(a+b)(x-y)
ax + bx -ay -by = (a+b)(x-y)
Method-2:–
Given expression is ax + bx -ay -by
=>(ax-ay)+(bx-by)
=>a(x-y)+b(x-y)
=>(x-y)(a+b)
ax + bx -ay -by = (a+b)(x-y)
Answer:–
The factorization of the given expression is ax + bx -ay -by = (a+b)(x-y)