The particular integral of the differential equation F(D)y=Q is equual to
(A) 1/F(D)
(B) 1.Q/F(D)
(C) Q.F(D)
(

2 thoughts on “The particular integral of the differential equation F(D)y=Q is equual to<br />(A) 1/F(D)<br />(B) 1.Q/F(D)<br />(C) Q.F(D)<br />(”

1. SOLUTION

   TO CHOOSE THE CORRECT OPTION

   The particular integral of the differential equation F(D)y=Q is equal to

   (A) 1/F(D)

   (B) 1.Q/F(D)

   (C) Q.F(D)

   (D) all of the above

   EVALUATION

   Here the given differential equation is

   F(D)y = Q

   Now the complementary function is obtained by solving the differential equation F(D)y = 0

   Also the particular integral is obtained by solving

   [tex] \displaystyle \sf{ = \frac{1}{Q}F(D)}[/tex]

   FINAL ANSWER

   Hence the correct option is

   [tex] \displaystyle \sf{ (B) \: \: \: \frac{1}{Q}F(D)}[/tex]

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2. Answer:

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