cosec 90 – theta minus sin 90 minus theta into cos theta minus sin theta into 10 theta + cot theta is equal to 1 About the author Ayla
Answer: sin(90 o −θ)=cosθ, cos(90 o −θ)=sinθ, cosec(90 o −θ)=secθ, cot(90 o −θ)=tanθ, sec(90 o −θ)=cosecθ, tan(90 o −θ)=cotθ ∴ cosec(90−θ)sin(90−θ)cot(90−θ) cos(90−θ)sec(90−θ)tanθ + cotθ tan(90−θ) ∴ sin(90−θ) 1 ×sin(90−θ)×tanθ sinθ× cos(90−θ) 1 ×tanθ + cotθ cotθ = cosθ 1 ×cosθ sinθ× sinθ 1 +1 Reply
Answer:
sin(90
o
−θ)=cosθ, cos(90
o
−θ)=sinθ,
cosec(90
o
−θ)=secθ, cot(90
o
−θ)=tanθ,
sec(90
o
−θ)=cosecθ, tan(90
o
−θ)=cotθ
∴
cosec(90−θ)sin(90−θ)cot(90−θ)
cos(90−θ)sec(90−θ)tanθ
+
cotθ
tan(90−θ)
∴
sin(90−θ)
1
×sin(90−θ)×tanθ
sinθ×
cos(90−θ)
1
×tanθ
+
cotθ
cotθ
=
cosθ
1
×cosθ
sinθ×
sinθ
1
+1