urgent urgent!!!6 years ago, a man’s age was six times the age of his daughter. After 4 years, thrice his age will be equal to eig

urgent urgent!!!6 years ago, a man’s age was six times the age of his daughter. After 4 years, thrice his age will be equal to eight times his daughter’s age. What are their present ages? Find it.

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  1. Answer:

    Let the age of man be x

    and the age of his son be y

    According to the question:

    After 6 years :

    (x+6)=3(y+6)

    ⇒x−3y=12⟶(i)

    Three years ago :

    x−3=9(y−3)

    ⇒x−3=9y−27

    ⇒x−9y=−24⟶(ii)

    Solving (i) and (ii),

    6y=36

    ⇒y=6

    Putting value of y in equation (i),

    x−3xy=12

    ∴x=12+18

    x=30

    ∴ Age of man =30 years.

    Age of son =6 years

    I hope this helps!

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