two dice are rolled simultaneously . find the probability of : getting a multiple of 4 on the one dice and 3 on the other dice , and getting a sum of multiple of 3 About the author Peyton
Answer: Step-by-step explanation: n(S)=6×6=36 1) let A be the event getting 4 on the one dice and 3 on the other dice A={ (4,3),(3,4) } n(A)=2 ∴P(A)=n(A)/n(S) ∴p(A)=2/36 ∴p(A)=1/18 2) Let B be the event getting sum of multiple of 3 B={ (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3),(6,6) } n(B)= 12 ∴P(B)=n(B)/n(S) ∴P(B)=12/36 ∴P(B)=1/3 Hope it will help u… Reply
Answer:
Step-by-step explanation:
n(S)=6×6=36
1) let A be the event getting 4 on the one dice and 3 on the other dice
A={ (4,3),(3,4) }
n(A)=2
∴P(A)=n(A)/n(S)
∴p(A)=2/36
∴p(A)=1/18
2) Let B be the event getting sum of multiple of 3
B={ (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3),(6,6) } n(B)= 12
∴P(B)=n(B)/n(S)
∴P(B)=12/36
∴P(B)=1/3
Hope it will help u…