In a binomial experiment the probability of success is 0.06. What is the probability of two successes in seven trials? About the author Aaliyah
Answer: Step-by-step explanation: Fill in the values into the base equation; p(X=x)=(nCr)(0.06)ˣ(0.94)⁽ⁿ⁻ˣ⁾ Where n is the number of trials, x is the probability of success, p is probability of success and q is the probability of failure. X~B(7, 0.06) P(X=2)=(7C2)(0.06)²(0.94)⁵ P(X=2)=0.05548 Double check by inputting into a scientific calculator; P(X=2)=0.05548 ≈ 0.0555 Reply
Answer: 0.055 Step-by-step explanation: Probability of success = 0.06 Probability of failing = 1 – 0.06 = 0.94 Probability of 2 successes in 7 trials = ⁷C2 × (0.06)² × (0.94)⁵ = 7!/(2! ×5!) × (0.06)² × (0.94)⁵ ~ 21 × 0.0026 = 0.055 Reply
Answer:
Step-by-step explanation:
Fill in the values into the base equation;
p(X=x)=(nCr)(0.06)ˣ(0.94)⁽ⁿ⁻ˣ⁾
Where n is the number of trials, x is the probability of success, p is probability of success and q is the probability of failure.
X~B(7, 0.06)
P(X=2)=(7C2)(0.06)²(0.94)⁵
P(X=2)=0.05548
Double check by inputting into a scientific calculator;
P(X=2)=0.05548 ≈ 0.0555
Answer:
0.055
Step-by-step explanation:
Probability of success = 0.06
Probability of failing = 1 – 0.06 = 0.94
Probability of 2 successes in 7 trials
= ⁷C2 × (0.06)² × (0.94)⁵
= 7!/(2! ×5!) × (0.06)² × (0.94)⁵
~ 21 × 0.0026
= 0.055