find the ratio in which the line segment joining the point 5,-6and -1,-4 I’d divided by y axis​

2 thoughts on “find the ratio in which the line segment joining the point 5,-6and -1,-4 I’d divided by y axis​”

1. Answer:

   using section formula

   =m1×x2+m2×x1/m1+m2 or m1×y2+m2×m1/m1+m2

   then you get your answer?

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2. Answer:

   5:1

   Step-by-step explanation:

   Let the ratio be [tex]k:1[/tex]

   Since it is cut by y axis, the x- coordinate of the y axis is 0.

   Let the point on the y axis be [tex](0,y)[/tex]

   By section formula,

   [tex]x = \frac{mx2+nx1}{m+n}[/tex] when a line segment joining the point (x1,y1) and (x2,y2) is divided by (x,y) in the ratio of m:n

   P(5,-6)

   Q(-1,-4)

   [tex]0=\frac{k(-1)+1(5)}{k+1}\\0=5-k\\k=5[/tex]

   The ratio of division is 5:1

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