Answer: 50 points ke questions please Step-by-step explanation: Answer Open in answr app Open_in_app (i) x + y =5 and 2x –3y = 4 By elimination method x + y =5 … (i) 2x –3y = 4 … (ii) Multiplying equation (i) by (ii), we get 2x + 2y = 10 … (iii) 2x –3y = 4 … (ii) Subtracting equation (ii) from equation (iii), we get 5y = 6 y = 6/5 Putting the value in equation (i), we get x = 5 – (6/5) = 19/5 Hence, x = 19/5 and y = 6/5 By substitution methodx + y = 5 … (i) Subtracting y both side, we get x = 5 – y … (iv) Putting the value of x in equation (ii) we get 2(5 – y) – 3y = 4 -5y = – 6 y = -6/-5 = 6/5 Putting the value of y in equation (iv) we get x = 5 – 6/5 x = 19/5 Hence, x = 19/5 and y = 6/5 again Reply
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50 points ke questions please
Step-by-step explanation:
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Open in answr app
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(i) x + y =5 and 2x –3y = 4
By elimination method
x + y =5 … (i)
2x –3y = 4 … (ii)
Multiplying equation (i) by (ii), we get
2x + 2y = 10 … (iii)
2x –3y = 4 … (ii)
Subtracting equation (ii) from equation (iii), we get
5y = 6
y = 6/5
Putting the value in equation (i), we get
x = 5 – (6/5) = 19/5
Hence, x = 19/5 and y = 6/5
By substitution methodx + y = 5 … (i)
Subtracting y both side, we get
x = 5 – y … (iv)
Putting the value of x in equation (ii) we get
2(5 – y) – 3y = 4
-5y = – 6
y = -6/-5 = 6/5
Putting the value of y in equation (iv) we get
x = 5 – 6/5
x = 19/5
Hence, x = 19/5 and y = 6/5 again