The ratio of present ages of two brothers is 1 : 2 and5 years back the ratio was 1 : 3. What will be theratio of their ages after 5 years About the author Faith
Answer: 3:5 Step-by-step explanation: x-5/2x-5 = 1/3 3x-15 = 2x-5 3x-15+5 = 2x 3x – 10 = 2x 3x-2x = 10 x = 10 2x = 20 After 5 years x+5/2x + 5 10+5/20+5 15/25 3/5 3:5 Answer. Reply
AnswEr : ❍ Given that, the ratio of present ages of two brothers is 1: 2. So, let’s say that the present ages of the two brothers be x and 2x respectively. ⭒ By Given C O N D I T I O N : Five years back, the ratio of their ages (both brother’s ages) was 1: 3. Therefore, ☆ Five years ago their ages — Younger brother = (x – 5) Elder brother = (2x – 5) ⠀⠀⠀ Now, ⠀⠀⠀⠀ [tex]\dashrightarrow\sf \bigg\{\dfrac{x – 5}{2x – 5}\bigg\} = \bigg\{\dfrac{1}{3}\bigg \} \\ \\\\\dashrightarrow\sf 3\Big\{x – 5\Big\} = \Big\{2x – 5\Big\} \\ \\ \ \\\dashrightarrow\sf 3x – 15 = 2x – 5\\\ \\ \\\dashrightarrow\sf 3x – 2x = – 5 + 15\\\ \\ \ \\\dashrightarrow\underline{\boxed{\frak{\pmb{\pink{x = 10 }}}}}\;\bigstar[/tex] Hence, Present ages of both brother are, x = 10 years 2x = 2(10) = 20 years ⠀⠀⠀⠀ [tex]\therefore{\underline{\textsf{Present~ages~of~two~brothers~are~\textbf{10 years and 20 years}.}}}[/tex] ⠀⠀⠀ [tex]\rule{300px}{.3ex}[/tex] ★ R A T I O : After five years the ratio their ages will be — [tex]:\implies\sf \dfrac{10 + 5}{20 + 5} \\\\\\:\implies\sf \cancel\dfrac{15}{25} \\ \\ \\:\implies{\boxed{\underline{\frak{\purple{\dfrac{3}{5}}}}}}\;\bigstar[/tex] ⠀⠀⠀⠀ [tex]\therefore{\underline{\textsf{Hence,~the~required~ratio~of~their~ages~is~ \textbf{3:5}.}}}[/tex]⠀⠀⠀⠀ Reply
Answer:
3:5
Step-by-step explanation:
x-5/2x-5 = 1/3
3x-15 = 2x-5
3x-15+5 = 2x
3x – 10 = 2x
3x-2x = 10
x = 10
2x = 20
After 5 years
x+5/2x + 5
10+5/20+5
15/25
3/5
3:5 Answer.
AnswEr :
❍ Given that, the ratio of present ages of two brothers is 1: 2. So, let’s say that the present ages of the two brothers be x and 2x respectively.
⭒ By Given C O N D I T I O N :
Therefore,
☆ Five years ago their ages —
⠀⠀⠀
Now,
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[tex]\dashrightarrow\sf \bigg\{\dfrac{x – 5}{2x – 5}\bigg\} = \bigg\{\dfrac{1}{3}\bigg \} \\ \\\\\dashrightarrow\sf 3\Big\{x – 5\Big\} = \Big\{2x – 5\Big\} \\ \\ \ \\\dashrightarrow\sf 3x – 15 = 2x – 5\\\ \\ \\\dashrightarrow\sf 3x – 2x = – 5 + 15\\\ \\ \ \\\dashrightarrow\underline{\boxed{\frak{\pmb{\pink{x = 10 }}}}}\;\bigstar[/tex]
Hence,
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[tex]\therefore{\underline{\textsf{Present~ages~of~two~brothers~are~\textbf{10 years and 20 years}.}}}[/tex]
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[tex]\rule{300px}{.3ex}[/tex]
★ R A T I O :
[tex]:\implies\sf \dfrac{10 + 5}{20 + 5} \\\\\\:\implies\sf \cancel\dfrac{15}{25} \\ \\ \\:\implies{\boxed{\underline{\frak{\purple{\dfrac{3}{5}}}}}}\;\bigstar[/tex]
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[tex]\therefore{\underline{\textsf{Hence,~the~required~ratio~of~their~ages~is~ \textbf{3:5}.}}}[/tex]⠀⠀⠀⠀