SOLVE USING SUBSTITUTION METHOD:
[tex] \sqrt{2} x + \sqrt{3 \: } y = 0 \\ \sqrt{3} x – \sqrt{8} y = 0[/tex]
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1 thought on “SOLVE USING SUBSTITUTION METHOD:<br />[tex] \sqrt{2} x + \sqrt{3 \: } y = 0 \\ \sqrt{3} x – \sqrt{8} y = 0[/tex]<br />​”

1. Step-by-step explanation:

   from equation 1) we have

   x= -√3y/√2.

   on substituting this expression of x in equation 2) we get_

   √3x – √8y = 0

   √3(-√3y/√2) – √8y = 0

   -3y/√2 – √8y = 0

   (-3y – 4y) / √2 = 0

   -3y – 4y = 0

   -7y = 0

   y= 0.

   then , from equation 1) we substitute value of y= 0

   we get,

   x= -√3×0/√2

   x = 0

   hence, x= 0 and y= 0

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