A² + 1/a² = 27
a – 1/a = ?

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2 thoughts on “A² + 1/a² = 27<br />a – 1/a = ?<br /><br />❌no spam❌<br />❌no copied answer ❌​”

1. Answer:

   Given:-

   [tex]

   a²+\dfrac{1}{a²}a²+a²1

   [/tex]

   To Find:-

   [tex]a+\dfrac{1}{a}a+a1

   [tex]a+\dfrac{1}{a}a+a1[/tex]

   Identity used:-

   ( a -b )² = a² + b² – 2ab

   Solution:-

   Comparing the given terms with this identity.

   So,

   [tex]⇒ ( a+\dfrac{1}{a}a+a1 )² = a²+\dfrac{1}{a²}-2a²+a²1−2

   ⇒ ( a+\dfrac{1}{a}a+a1 )² = 27 – 2

   ⇒ ( a+\dfrac{1}{a}a+a1 )² = 25

   ⇒ a+\dfrac{1}{a}a+a1 = √25

   ⇒ a+\dfrac{1}{a}a+a1 = ±5

   We will ignore negative term.[/tex]

   Hence, the value of a+\dfrac{1}{a}a+a1 is +5.

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2. Answer:

   ♧ ᴀɴsᴡᴇʀ♧

   Given that,

   A² + 1/a² = 27

   so, (A)² + (1/a)² – 2a.1/a = 27a.1/a

   => (a – 1/a)² = 27–2

   => a – 1/a = √25

   => a – 1/a = 5

   Hence, a – 1/a = 5 .

   ♡ ᴍɪss_ɪɴɴᴏᴄᴇɴᴛ♡

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