If the perimeter of a rhombus is 40 cm and length of one of the diagonals is 12cm. What is the area of the rhombus ? About the author Amelia
Answer: 96cm square Step-by-step explanation: Given the perimeter of rhombus is 40 cm and one diagonal is 12 cm We know that perimeter of rhombus=2 p 2 +q 2 where -p and q are diagonal of rhombus ∴40=2 (12) 2 +q 2 ⇒20= 144+q 2 ⇒400=144+q 2 ⇒q 2 =400−144=256 ⇒q=16 cm Then length of second diagonal is 16 cm Then area of rhombus= 2 p×q = 2 12×16 = 2 192 =96Cm square Reply
Answer:
96cm square
Step-by-step explanation:
Given the perimeter of rhombus is 40 cm and one diagonal is 12 cm
We know that perimeter of rhombus=2
p
2
+q
2
where -p and q are diagonal of rhombus
∴40=2
(12)
2
+q
2
⇒20=
144+q
2
⇒400=144+q
2
⇒q
2
=400−144=256
⇒q=16 cm
Then length of second diagonal is 16 cm
Then area of rhombus=
2
p×q
=
2
12×16
=
2
192
=96Cm square