1. The simple interest on some principal at some rate for 3 years is 525. At the
same rate, the compound interest on 1600 for

1. The simple interest on some principal at some rate for 3 years is 525. At the
same rate, the compound interest on 1600 for 2 years is 164. What is the
principal?
(1) * 4500
(2) 3500
(3) 3000
(4) * 4000​

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  1. Answer:

    Here is your answer

    R = 3 years

    SI = Rs 525

    Let rate of interest= R and principal be x

    Now

    SI = PRT/100

    \begin{gathered}525 = \frac{x \times r \times 3}{100} \\ r = \frac{525 \times 100}{3x} \\ r = \frac{17500}{x} \%\end{gathered}

    525=

    100

    x×r×3

    r=

    3x

    525×100

    r=

    x

    17500

    %

    Hence For Compound Interest

    T = 2 years

    P = Rs 1600

    CI = 164

    R = 17500/x %

    A = 1600 + 164 = Rs 1764

    As we know the formula

    A = P{1+R/100)^t

    \begin{gathered}1764 = 1600(1 + \frac{17500}{x \times 100} ) {}^{2} \\ \frac{1764}{1600} = (1 + \frac{175}{x} ) {}^{2} \\ \frac{441}{400} = (1 + \frac{175}{x} ) {}^{2} \\ ( \frac{21}{20} ) {}^{2} = (1 + \frac{175}{x} ) {}^{2} \\ on \: comparing \\ \frac{21}{20} = 1 + \frac{175}{x} \\ \frac{21}{20} – 1 = \frac{175}{x} \\ \frac{21 – 20}{20} = \frac{175}{x} \\ \frac{1}{20} = \frac{175}{x} \\ x = 175 \times 20 \\ x = 3500\end{gathered}

    1764=1600(1+

    x×100

    17500

    )

    2

    1600

    1764

    =(1+

    x

    175

    )

    2

    400

    441

    =(1+

    x

    175

    )

    2

    (

    20

    21

    )

    2

    =(1+

    x

    175

    )

    2

    oncomparing

    20

    21

    =1+

    x

    175

    20

    21

    −1=

    x

    175

    20

    21−20

    =

    x

    175

    20

    1

    =

    x

    175

    x=175×20

    x=3500

    Therefore

    Principal is Rs 3,500

    Reply

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