6. Two years ago, Mr Singh was 7 times as old as his son. In 3 years’ time, he will be 4 times as old as his son. Find Mr Singh’s
present age.
Please use a pair of simultaneous equations to solve this question. I will mark the correct answer as the brainliest.
Answer:
Singh’s present age is 37
His son’s present age is 7
All the best
Mark me brainliest and flw me
Step-by-step explanation:
2 years ago, Mr. Singh was 7 times as old as his son (given)
Let 2 years ago his son’s age = x. Then, 2 years ago singh’s age = 7x.
3 years hence, Mr. Singh will be 4 times as old as his Son (given)
3 years hence, their ages be 7x+5 and x+5
(Note: We add 5 because After 3 years + before 2 years = 5years )
∴ 7x+5 = 4(x+5)
∴ 7x+5 = 4x+20
∴ 7x – 4x = 20-5
∴3x = 15
∴x=5
∴ Singh’s present age
= 7x + 2 = 37 years
and His son’s present age
=x+2 = 7 years
Verifying:
2years ago :
Singh’s age: 37-2 = 35
Son’s age: 7-2 = 5
35 is a 7time of 5
After 3 years:
Singh’s age 37+3 = 40
Son’s age: 7+ 3 = 10
40 is 4times of 10
Hope its clear
All the best
Mark me brainliest and flw me