Step-by-step explanation: Let the points be A(-2,5) B(0, 1) C(2,3) AB = √(0+2)^2+(1-5)^2 = √4+16 = √20 BC = √(2-0)^2+(3-1)^2 = √4+4=√8 AC = √(2+2)^2+(3-5)^2 = √4^2+(-2)^2 = √16+4=√20 Since AB = AC hence proved Reply
Step-by-step explanation:
Let the points be
A(-2,5)
B(0, 1)
C(2,3)
AB = √(0+2)^2+(1-5)^2 = √4+16 = √20
BC = √(2-0)^2+(3-1)^2 = √4+4=√8
AC = √(2+2)^2+(3-5)^2 = √4^2+(-2)^2 = √16+4=√20
Since AB = AC hence proved