What would be the pH of a solution obtained by mixing 100 mL of 0.1 (N) HCL and 100 mL of (N) H2SO4 ? About the author Savannah
Answer: The pH of the solution obtained by mixing 100 ml of a solution of pH 3 with 400 ml of a solution of pH 4 is (a) 100 ml of a solution of pH = 3 [H + ]=10 −pH =10 −3 M (b) 400 ml of a solution of pH = 4 [H + ]=10 −pH =10 −4 M When two solutions are mixed, [H + ]= 100+400 100×10 −3 +400×10 −4 =0.00028 M =2.8× 10 −4 M pH=−log[H + ]=−log (2.8× 10 −4 )=−(log 2.8)−(log 10 −4 )=4−log 2.8 Hence, option (C) is the correct answer. Reply
Answer:
The pH of the solution obtained by mixing 100 ml of a solution of pH 3 with 400 ml of a solution of pH 4 is
(a) 100 ml of a solution of pH = 3
[H
+
]=10
−pH
=10
−3
M
(b) 400 ml of a solution of pH = 4
[H
+
]=10
−pH
=10
−4
M
When two solutions are mixed,
[H
+
]=
100+400
100×10
−3
+400×10
−4
=0.00028 M =2.8× 10
−4
M
pH=−log[H
+
]=−log (2.8× 10
−4
)=−(log 2.8)−(log 10
−4
)=4−log 2.8
Hence, option (C) is the correct answer.