7. Write a Pythagorean triplet whose members are formed by the given natural numbers.
( (a) 6 b) 14​

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1. Answer:

   a)6,8and 10=m=3,2m=6,mSQ-1=8,mSQ+1=10

   b)14,48, and 50=m=7,2m=14,mSQ-1=48,mSQ+1=50

   Step-by-step explanation:

   a)As we know 2m, mSQ

   +1 and mSQ−1 from a Pythagorean triplet for any number , m>1

   Let us assume 2m=6

   Therefore, m =3

   mSQ-1=3*3-1=8

   mSQ+1=3*3+1=10

   Hence the triplet is 6,8, and 10 Answer

   b)As we know 2m, mSQ+1 and mSQ−1 from a Pythagorean triplet for any number , m>1

   Let us assume 2m=14

   Therefore, m =7

   mSQ-1=7*7-1=48

   mSQ+1=7*7+1=50

   Hence the triplet is 14,48, and 50 Answer

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