0.14: Ifw is a emplex cube root of unity, there find value of
(1-6 + c) + (1 – – – W’) – (1 – w + o)​

2 thoughts on “0.14: Ifw is a emplex cube root of unity, there find value of<br />(1-6 + c) + (1 – – – W’) – (1 – w + o)​”

1. Step-by-step explanation:

   Correct option is

   D

   −128ω

   2

   Since w is the imaginary cube root of unity

   w

   3

   =1 and

   1+w+w

   2

   =0 …(i)

   Hence

   (1+w−w

   2

   )

   7

   =((1+w)−w

   2

   )

   7

   =(−w

   2

   −w

   2

   )

   7

   …from i

   =(−2w

   2

   )

   7

   =−128w

   14

   =−128w

   12

   .w

   2

   =−128(w

   3

   )

   4

   .w

   2

   =−128w

   2

   …since w

   3

   =1.

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2. Answer:

   Hint: The cube roots of unity can be defined as the numbers which when raised to the power of 3 gives the result as 1 i.e., in simple words, the cube root of unity is the cube root of 1 i.e., 3√1. To show that (2−w)(2−w2)(2−w10)(2−w11)=49 hence, consider the properties of the cube root to obtain the given equation

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