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[tex](2cos^2A-1)^2÷cos^4A-sin^4=1-2sin^2A\ \textless \ br /\ \textgreater \ (2 \cos(2) a – 1) {}^{2} \div \cos(4) – \sin(4

By Jasmine

[tex](2cos^2A-1)^2÷cos^4A-sin^4=1-2sin^2A\ \textless \ br /\ \textgreater \ (2 \cos(2) a – 1) {}^{2} \div \cos(4) – \sin(4) = 1 – 2 \sin(2) a(2cos(2)a−1)2÷cos(4)−sin(4)=1−2sin(2)a\ \textless \ br /\ \textgreater \ [/tex]
Anyone ?​

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Jasmine

The ratio of boys to girls in Ms. Cunningham’s class is 2 to 3. There are 18 girls in the class.

Q.4.write ‘T’ for true and ‘F’ for False:
i. A trapezium is a quadrilateral, whose one opposite pair is parallel.​

1 thought on “<br />[tex](2cos^2A-1)^2÷cos^4A-sin^4=1-2sin^2A\ \textless \ br /\ \textgreater \ (2 \cos(2) a – 1) {}^{2} \div \cos(4) – \sin(4”

  1. Answer:

    [tex][/tex]

    • Force is push or pull acting on a body which tends to change its state of rest or of motion.
    • It is denoted by “F”.
    Reply

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