Answer: xy = ab Step-by-step explanation: Given: We are given that HCF(a , b) = x, LCM(a , b) = y To find: According to the question, we need to find the value of xy, if a and b are co – primes. Solution: Co – primes are the pair of numbers, whose HCF is 1 and LCM is their product. → HCF(a , b) = 1 , LCM(a , b) = a × b → x = 1 , y = a × b On substituting the values in xy, ⇒ xy = 1 × (a × b) ⇒ xy = ab Hence, xy = ab. Alternative method: We know that, product of HCF and LCM of two numbers is equal to product of their numbers. → HCF(a , b) × LCM(a , b) = a × b → x × y = a × b → xy = ab Final Answer: The value of xy is ab. # Learn More: 1. The hcf of two numbers is 145 and their lcm is 2175 , if one of the numbers is 725 find the other number https://brainly.in/question/39524708 Reply
Answer: xy = ab
Step-by-step explanation:
Given: We are given that HCF(a , b) = x, LCM(a , b) = y
To find: According to the question, we need to find the value of xy, if a and b are co – primes.
Solution:
Co – primes are the pair of numbers, whose HCF is 1 and LCM is their product.
→ HCF(a , b) = 1 , LCM(a , b) = a × b
→ x = 1 , y = a × b
On substituting the values in xy,
⇒ xy = 1 × (a × b)
⇒ xy = ab
Hence, xy = ab.
Alternative method:
We know that, product of HCF and LCM of two numbers is equal to product of their numbers.
→ HCF(a , b) × LCM(a , b) = a × b
→ x × y = a × b
→ xy = ab
Final Answer: The value of xy is ab.
# Learn More:
1. The hcf of two numbers is 145 and their lcm is 2175 , if one of the numbers is 725 find the other number
https://brainly.in/question/39524708