Question 2
If 8 times their 17th term of an A.P is equal to 6 times its 9th term, then the 41st term
of the A.P is?​

1 thought on “Question 2<br />If 8 times their 17th term of an A.P is equal to 6 times its 9th term, then the 41st term<br />of the A.P is?​”

1. Answer:

   T

   n

   =a+(n−1)d

   Where a is the first term, d is the common difference and T

   n

   denotes the n-th term of an AP.

   Given:

   19=a+5d

   41=a+16d

   Solving the above equations gives: d=2,a=9

   Therefore, T

   40

   =9+39⋅2=

   87

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