[tex]\huge\red{Question}[/tex] Insert a rational number between 2/9 and 3/8,and arrange in descending order About the author Savannah
First we have to find the LCM of denominators LCM of 9 and 8 = 72 [tex] \frac{2}{9} = \frac{2 \times 8}{9 \times 8} = \frac{16}{72} \\ \frac{3}{8} = \frac{3 \times 9}{8 \times 9} = \frac{27}{72} [/tex] Now there are more than one rational number between 16 and 27 you can write any one so [tex] \frac{27}{72} > \frac{20}{72} > \frac{16}{72} \\ [/tex] It is in descending order. You said for only one, but you can write more than one. hope it helps. Reply
[tex]\huge\mathfrak\red{Question}[/tex] Insert a rational number between 2/9 and 3/8,and arrange in descending order [tex]\huge\mathfrak\green{Answer}[/tex] Take LCM of 8 and 9 and make their denominators same. 2/9 = 16/72 3/8 = 27/72 All numbers, 17/72, 18/72, 19/72, 20/72.. 26/72 are in between the two numbers. Reply
First we have to find the LCM of denominators
LCM of 9 and 8 = 72
[tex] \frac{2}{9} = \frac{2 \times 8}{9 \times 8} = \frac{16}{72} \\ \frac{3}{8} = \frac{3 \times 9}{8 \times 9} = \frac{27}{72} [/tex]
Now there are more than one rational number between 16 and 27 you can write any one so
[tex] \frac{27}{72} > \frac{20}{72} > \frac{16}{72} \\ [/tex]
It is in descending order.
You said for only one, but you can write more than one.
hope it helps.
[tex]\huge\mathfrak\red{Question}[/tex]
Insert a rational number between 2/9 and 3/8,and arrange in descending order
[tex]\huge\mathfrak\green{Answer}[/tex]
Take LCM of 8 and 9 and make their denominators same.
2/9 = 16/72
3/8 = 27/72
All numbers,
17/72, 18/72, 19/72, 20/72..
26/72 are in between the two numbers.