Hello. good wali evening to all….Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 ༶•┈┈⛧┈♛ About the author Emma
Step-by-step explanation: First deduct the remainders from each term 398 – 7 =391 436–11 = 425 542–15 =527 Next find the HCF of the terms that you get 391 = 17×23 425 = 5x5x17 527 = 17×31 The HCF is 17. The answer is the HCF or 17. Check 398/17 = 23 + 7 remainder 436/17 = 25 + 11 remainder 542/17 = 31 + 15 remainder ___abb toh bata do khushi_ kya jawab hai tmhara_ Reply
Answer: HCF of 398 ,436, 542 is 17 because the greatest common factor from all the number is 17 only so we can say that the largest number that will divide 398, 436, 542, leaving remainders 7, 11, 15 respectively is 17 . Reply
Step-by-step explanation:
First deduct the remainders from each term
398 – 7 =391
436–11 = 425
542–15 =527
Next find the HCF of the terms that you get
391 = 17×23
425 = 5x5x17
527 = 17×31
The HCF is 17.
The answer is the HCF or 17.
Check 398/17 = 23 + 7 remainder
436/17 = 25 + 11 remainder
542/17 = 31 + 15 remainder
___abb toh bata do khushi_ kya jawab hai tmhara_
Answer:
HCF of 398 ,436, 542 is 17 because the
greatest common factor from all the number is
17 only
so we can say that the largest number that
will divide 398, 436, 542, leaving remainders
7, 11, 15 respectively is 17 .