Answer: A+B =90° ⇒A= 90°-B tanA = 3/4 ⇒tan(90°-B) = 3/4 ∵ tan(90°-A) = cotA ∴ tan(90°-B) = 3/4 ⇒cotB = 3/4 Reply
Answer:
A+B =90°
⇒A= 90°-B
tanA = 3/4
⇒tan(90°-B) = 3/4
∵ tan(90°-A) = cotA
∴ tan(90°-B) = 3/4
⇒cotB = 3/4