The two palm trees are of equal heights and are standing opposite each other on either side of the river, which is 80 m wide. From a point O between them on the river the angles of elevation of the top of the trees are 60° and 30°, respectively. Find the height of the trees and the distances of the point O from the trees.
Given measures according to the question
ʜᴇɪɢʜᴛ ᴏғ ᴛʜᴇ ᴛʀᴇᴇs = 34.64 m
ʜᴇɪɢʜᴛ ᴏғ ᴛʜᴇ ᴛʀᴇᴇs = 34.64 m
ᴅɪsᴛᴀɴᴄᴇ = 60 m.
Let Palm tree be poles
tan600=80-xb
3=80-xb
b=3x-803 ….(i)
and,
tan300=31=xa
x=a3 …(ii)
b=3a-803
Or
3a-b=803
❥︎ Now it is given that the heights are equal.
Hence
a=b=h
Therefore
2h=803
h=203
=2(17.32)
=34.64m
Hence
x= h3
=20(3)=60m
Let Palm tree be poles
tan600=80-xb
3=80-xb
b=3x-803 ….(i)
and,
tan300=31=xa
x=a3 …(ii)
b=3a-803
Or
3a-b=803
❥︎ Now it is given that the heights are equal.
Hence
a=b=h
Therefore
2h=803
h=203
=2(17.32)
=34.64m
Hence
x= h3
=20(3)=60m