Evaluate the following by using identity-1.
(i) (101)^2​

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1. Answer:

   (101)^2

   101)^2= (100+1)^2

   a = 100 b = 1

   {(a+b)^2 = a^2+b^2+2ab}=(100)^2+(1)^2+2(100)(1)

   10000+1+200

   =10201 Answer …

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