find the values ofp for whichthe equation 3x² – 5x – 2p = 0has real neal roots About the author Lyla
Answer: The value of p so that the equation 3x²-5x-2p=0 has equal roots is -25/24 and the root is 5/6. Given equation is 3x²-5x-2p=0. We have to find the value of p so that the equation has equal roots. For a quadratic equation to have equal roots b²-4ac should be equal to zero in the quadratic equation ax²+bx+c=0. Now comparing the equation with the standard equation ax²+bx+c=0 , we get a=3 , b=-5 , c=-2p Now, b²-4ac = 0 as the equation has equal roots (-5)²-4(3)(-2p)=0 25+24p=0 p = -25/24 Now the quadratic equation becomes 3x²-5x+25/12=0. Root of the equation is . Root of the equation is . Step-by-step explanation: Reply
Given equation is 3x² – 5x – 2p = 0 Comparing with standard quadratic equation ax² + bx + c = 0 we get a = 3 , b = -5 , c= 2p for real root b² – 4ac > 0 (5)² – 4(3)(2p) > 0 25 – 24p >0 p > 25/24 Reply
Answer:
The value of p so that the equation 3x²-5x-2p=0 has equal roots is -25/24 and the root is 5/6.
Given equation is 3x²-5x-2p=0.
We have to find the value of p so that the equation has equal roots.
For a quadratic equation to have equal roots b²-4ac should be equal to zero in the quadratic equation ax²+bx+c=0.
Now comparing the equation with the standard equation ax²+bx+c=0 , we get
a=3 , b=-5 , c=-2p
Now, b²-4ac = 0 as the equation has equal roots
(-5)²-4(3)(-2p)=0
25+24p=0
p = -25/24
Now the quadratic equation becomes 3x²-5x+25/12=0.
Root of the equation is .
Root of the equation is .
Step-by-step explanation:
Given equation is 3x² – 5x – 2p = 0
Comparing with standard quadratic equation
ax² + bx + c = 0 we get
a = 3 , b = -5 , c= 2p
for real root
b² – 4ac > 0
(5)² – 4(3)(2p) > 0
25 – 24p >0
p > 25/24