• Population of a town increases by 10% per year. Ifthe population of town is 2.00.000 at present, findthe population of the town after a year-(A) 2,10,000(B) 2,50.000(C) 2.80,000(D) 2,20,000 About the author Arya
Answer: Given:– Population of a town increases by 10% per year. If the population of town is 2,00,000 at present, find the population of the town after a year. To Find:– The population after 1 year. Note:– ●》Here, we will find how much population increases per year by multiplying 10% into total population ( unitary method ) then for finding population after a year, we will add the population increases per year by total population. ●》Percent ( % ) means per hundred i.e. [tex] n [/tex] % [tex] = \frac{n}{100} [/tex] Solution:– ☆ According to note first point~ ▪︎[tex] Population \ \ increases \ \ per \ \ year = 10 [/tex] % [tex] × Total \ \ Population [/tex] ☆ According to note second point~ ▪︎[tex] Population \ \ increases \ \ per \ \ year = \frac{10}{100} × 2,00,000 [/tex] ▪︎[tex] Population \ \ increases \ \ per \ \ year = \frac{20,00,000}{100} [/tex] ▪︎[tex] Population \ \ increases \ \ per \ \ year = 20,000 [/tex] [tex] \huge\pink{Population \ \ increases \ \ per \ \ year = 20,000} [/tex] __________________________ [tex] \huge\red{[ Now, Population \ \ after \ \ a \ \ year ]} [/tex] ☆ Accordingly to note first point only~ ▪︎[tex] Population \ \ after \ \ a \ \ year = Population \ \ increases \ \ per \ \ year + Total \ \ Population [/tex] ▪︎[tex] Population \ \ after \ \ a \ \ year = 20,000 + 2,00,000 [/tex] ☆ After adding~ ▪︎[tex] Population \ \ after \ \ a \ \ year = 2,20,000 [/tex] [tex] \huge\pink{Population \ \ after \ \ a \ \ year = 2,20,000} [/tex] Answer:– Hence, the Population of a town after a year = 2,20,000. :) Reply
Answer:
Given:–
Population of a town increases by 10% per year. If the population of town is 2,00,000 at present, find the population of the town after a year.
To Find:–
The population after 1 year.
Note:–
●》Here, we will find how much population increases per year by multiplying 10% into total population ( unitary method ) then for finding population after a year, we will add the population increases per year by total population.
●》Percent ( % ) means per hundred i.e. [tex] n [/tex] % [tex] = \frac{n}{100} [/tex]
Solution:–
☆ According to note first point~
▪︎[tex] Population \ \ increases \ \ per \ \ year = 10 [/tex] % [tex] × Total \ \ Population [/tex]
☆ According to note second point~
▪︎[tex] Population \ \ increases \ \ per \ \ year = \frac{10}{100} × 2,00,000 [/tex]
▪︎[tex] Population \ \ increases \ \ per \ \ year = \frac{20,00,000}{100} [/tex]
▪︎[tex] Population \ \ increases \ \ per \ \ year = 20,000 [/tex]
[tex] \huge\pink{Population \ \ increases \ \ per \ \ year = 20,000} [/tex]
__________________________
[tex] \huge\red{[ Now, Population \ \ after \ \ a \ \ year ]} [/tex]
☆ Accordingly to note first point only~
▪︎[tex] Population \ \ after \ \ a \ \ year = Population \ \ increases \ \ per \ \ year + Total \ \ Population [/tex]
▪︎[tex] Population \ \ after \ \ a \ \ year = 20,000 + 2,00,000 [/tex]
☆ After adding~
▪︎[tex] Population \ \ after \ \ a \ \ year = 2,20,000 [/tex]
[tex] \huge\pink{Population \ \ after \ \ a \ \ year = 2,20,000} [/tex]
Answer:–
Hence, the Population of a town after a year = 2,20,000.
:)
Answer:
2,20,000
Step-by-step explanation:
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