5 pencil and 7 pens together coast rs 50 whereas 7 pencil and 5 pen together cost rs 46 find the cost of one pencil and that of one pen About the author Lyla
Answer: Cost of one pencil = Rs. 3 and that of one pen = Rs. 5 Step-by-step explanation: Let cost of pencil be Rs. x Cost of pens be Rs. y 5 pencils and 7 pens together cost Rs. 50, So we get 5x+7y=50 Subtract 7y both side we get 5x=50–7y Divide by 5 we get x=10− 5 7 y Plug value of y which is factor of 5 to get whole number so plug y=5,10,15 we get fory=5 x=10− 5 7 y=10−7=3 for y=10 x=10− 5 7 y=10−14=−4 fory=15 x=10− 5 7 y=10−21=−11 Therefore, the required points are (3,5),(−4,10),(−11,15). Given that 7 pencils and 5 pens together cost Rs. 46 7x+5y=46 Subtract 7x both side we get 5y=46–7x Divide by 5 we get y=9.2–1.4x Plug x=0,2,4 we get for x=0 y=9.2–0=9.2 for x=2 y=9.2–2.8=6.4 forx=4 y=9.2–5.6=3.6 Therefore, the required points are (0,9.2),(2,6.4),(4,3.6). The graph is as shown below: Since the point of intersection is (3,5), Hence, the cost of one pencil is Rs. 3 and the cost of one pen is Rs. 5 Hope this will help you Mark me as brilliant Reply
Answer : Cost of one pencil is Rs.3 Cost of one pen is Rs.5 Given : 5 pencils and 7 pens together cost rupees 50 7 pencils and 5 pens together cost rupees 46 To find : Cost of one pencil and one pen Solution : Let the cost of one pencil be x Let the cost of pen be y According to question , 》5x + 7y = 50 》7x + 5y = 46 5x + 7y = 50 is eq (1) and 7x + 5y = 46 is eq (2) Now , we have to multiply 7 in equation (1) we get , 》7 × 5x + 7y = 50 》35x + 49y = 350 35x + 49y = 350 is eq (3) Now , we have to multiply 5 in equation (2) we get , 》5 × 7x + 5y = 46 》35x + 25y = 230 35x + 25y = 230 is eq (4) Now we have to equation 3 and equation 4 we get , 》35x + 49y = 350 – 35x + 25y = 230 》24y = 120 》y = 120/24 》y = 5 Now Substituting the value of y = 5 in equation (2) we get, 》7x + 5y = 46 》7x + 5(5) = 46 》7x + 25 = 46 》7x = 21 》x = 21/7 》x = 3 Cost of one pencil is Rs.3 Cost of one pen is Rs.5 Reply
Answer:
Cost of one pencil = Rs. 3 and that of one pen = Rs. 5
Step-by-step explanation:
Let cost of pencil be Rs. x
Cost of pens be Rs. y
5 pencils and 7 pens together cost Rs. 50,
So we get
5x+7y=50
Subtract 7y both side we get
5x=50–7y
Divide by 5 we get
x=10−
5
7
y
Plug value of y which is factor of 5 to get whole number so plug y=5,10,15 we get
fory=5
x=10−
5
7
y=10−7=3
for y=10
x=10−
5
7
y=10−14=−4
fory=15
x=10−
5
7
y=10−21=−11
Therefore, the required points are (3,5),(−4,10),(−11,15).
Given that 7 pencils and 5 pens together cost Rs. 46
7x+5y=46
Subtract 7x both side we get
5y=46–7x
Divide by 5 we get
y=9.2–1.4x
Plug x=0,2,4 we get
for x=0
y=9.2–0=9.2
for x=2
y=9.2–2.8=6.4
forx=4
y=9.2–5.6=3.6
Therefore, the required points are (0,9.2),(2,6.4),(4,3.6).
The graph is as shown below:
Since the point of intersection is (3,5),
Hence, the cost of one pencil is Rs. 3 and the cost of one pen is Rs. 5
Hope this will help you
Mark me as brilliant
Answer :
Given :
To find :
Solution :
According to question ,
》5x + 7y = 50
》7x + 5y = 46
5x + 7y = 50 is eq (1) and 7x + 5y = 46 is eq (2)
Now , we have to multiply 7 in equation (1) we get ,
》7 × 5x + 7y = 50
》35x + 49y = 350
35x + 49y = 350 is eq (3)
Now , we have to multiply 5 in equation (2) we get ,
》5 × 7x + 5y = 46
》35x + 25y = 230
35x + 25y = 230 is eq (4)
Now we have to equation 3 and equation 4 we get ,
》35x + 49y = 350 – 35x + 25y = 230
》24y = 120
》y = 120/24
》y = 5
Now Substituting the value of y = 5 in equation (2) we get,
》7x + 5y = 46
》7x + 5(5) = 46
》7x + 25 = 46
》7x = 21
》x = 21/7
》x = 3