5 houses in a row are numbered consecutively.. If total of their house numbers is 405, find the greatest house number.. A)105 B)83 C)205 D)73 About the author Eloise
Answer :- Let the numbers of houses be x , x + 1 , x + 2 , x + 3 and x + 4 According to the question :- → Total of their house numbers = 405 → x + x + 1 + x + 2 + x + 3 + x + 4 = 405 → x + x + x + x + x + 1 + 2 + 3 + 4 = 405 → 5x + 10 = 405 → 5x = 405 – 10 → 5x = 395 → x = 395 / 5 → x = 79 House numbers :- x = 79 x + 1 = 79 + 1 = 80 x + 2 = 79 + 2 = 81 x + 3 = 79 + 3 = 82 x + 4 = 79 + 4 = 83 Greatest house number = 83 Reply
Answer :-
Let the numbers of houses be x , x + 1 , x + 2 , x + 3 and x + 4
According to the question :-
→ Total of their house numbers = 405
→ x + x + 1 + x + 2 + x + 3 + x + 4 = 405
→ x + x + x + x + x + 1 + 2 + 3 + 4 = 405
→ 5x + 10 = 405
→ 5x = 405 – 10
→ 5x = 395
→ x = 395 / 5
→ x = 79
House numbers :-
Greatest house number = 83