A cow has four legs if there are x Cos then write the equation for total number of legs x cows About the author Mia
Answer: Let no. of hens be x and no. of cows be y. For heads the equation is x + y = 50 (head count is 50) For legs the equation is 2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs) From head count equation y = 50 – x substituting this in leg count equation we get 2x + 4(50 – x) = 144 2x + 200 – 4x = 144 -2x = 144 – 200 -2x = – 56 x = 28 Substituting in headcount equation we get y = 50 – 28 So y = 22 So there are 28 hens and 22 cows on the farm Reply
Answer:
Let no. of hens be x and no. of cows be y. For heads the equation is
x + y = 50 (head count is 50)
For legs the equation is
2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs)
From head count equation
y = 50 – x
substituting this in leg count equation we get
2x + 4(50 – x) = 144
2x + 200 – 4x = 144
-2x = 144 – 200
-2x = – 56
x = 28
Substituting in headcount equation we get
y = 50 – 28
So y = 22
So there are 28 hens and 22 cows on the farm
Answer:
4x
Step-by-step explanation:
If 1 cow has 4 legs, then the x cows have 4x legs