the sum of two integers is -11 and their product is -80 what are the two integers? About the author Autumn
Answer: x = – 16 x = 5 Step-by-step explanation: Let one no be x. Other will be -11-x. So, product = x(-11-x) = -x(11+x) = -80 = x(11+x) = 80 [tex]11x + {x}^{2} = 80[/tex] [tex] {x}^{2} + 11x – 80 = 0[/tex] [tex] {x}^{2} + 16x – 5x – 80 = 0[/tex] [tex]x(x + 16) – 5(x + 16) = 0[/tex] [tex](x + 16)(x – 5) = 0[/tex] [tex]x = – 16 \\ x = 5[/tex] Reply
Answer:
x = – 16
x = 5
Step-by-step explanation:
Let one no be x.
Other will be -11-x.
So, product = x(-11-x) = -x(11+x) = -80 = x(11+x) = 80
[tex]11x + {x}^{2} = 80[/tex]
[tex] {x}^{2} + 11x – 80 = 0[/tex]
[tex] {x}^{2} + 16x – 5x – 80 = 0[/tex]
[tex]x(x + 16) – 5(x + 16) = 0[/tex]
[tex](x + 16)(x – 5) = 0[/tex]
[tex]x = – 16 \\ x = 5[/tex]