The 13th term of an A.P whose first term and common difference respectively are 3/2 and 2/3 About the author Ella
Answer: [tex]a = \frac{3}{2} \\ d = \frac{2}{3} \\ a13 = a + 12d \\ = \frac{3}{2} + 12 \times \frac{2}{3} \\ = \frac{3}{2} \: \: + 8 \\ = \frac{3 + 16}{2} \\ = \frac{19}{2} [/tex] IT IS THE CORRECT ANSWER PLS MARK AS BRAINLIEST Reply
Answer:
[tex]a = \frac{3}{2} \\ d = \frac{2}{3} \\ a13 = a + 12d \\ = \frac{3}{2} + 12 \times \frac{2}{3} \\ = \frac{3}{2} \: \: + 8 \\ = \frac{3 + 16}{2} \\ = \frac{19}{2} [/tex]
IT IS THE CORRECT ANSWER
PLS MARK AS BRAINLIEST