remainder in each case.[b] Find the smallest number which when divided by 40, 60 and 100 leaves 24 as therenainder in each case. About the author Alaia
Answer: Answer: LCM( 40 , 60 , 100 ) = 600. Required number = LCM + 24 = 624 . Step-by-step explanation: Hope its helps you very much Reply
Answer:
Answer: LCM( 40 , 60 , 100 ) = 600. Required number = LCM + 24 = 624 .
Step-by-step explanation:
Hope its helps you very much