Answer: [tex]\huge\underbrace\purple{\dag Question \dag}[/tex] if 2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1 than find the value of a [tex]\huge\underbrace\pink{\dag Answer \dag}[/tex] 2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1 [tex]f(2) = a( {2})^{2} – 3(a – 1)2 – 1 = 0 \\ 4a – 6a + 6 – 1 = 0 \\ – 2a + 5= 0 \\ – 2a = 0 – 5 \\ – 2a= – 5 \\ a = \frac{ – 5}{ – 2} \\ a = \boxed{ \frac{5}{2} } [/tex] ✯✯✯✯✯_________________________✯✯✯✯✯ [tex]\bold \star\red{\underline{\boxed{Hope \: it \: helps \: you}}}\star[/tex] [tex]\bold \star\orange{\underline{\boxed{Pls \: follow \: kar \: do}}}\star[/tex] [tex]\bold \star\red{\underline{\boxed{Pls \: mark \: me\: brainlist}}}\star[/tex] ✯✯✯✯✯_________________________✯✯✯✯✯ Reply
Answer:
a(2)²-3(a-1)2-1=0
4a-6a+6-1=0
-2a+5=0
-2a=-5
-a=-5/2
a=5/2
Answer:
[tex]\huge\underbrace\purple{\dag Question \dag}[/tex]
if 2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1 than find the value of a
[tex]\huge\underbrace\pink{\dag Answer \dag}[/tex]
2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1
[tex]f(2) = a( {2})^{2} – 3(a – 1)2 – 1 = 0 \\ 4a – 6a + 6 – 1 = 0 \\ – 2a + 5= 0 \\ – 2a = 0 – 5 \\ – 2a= – 5 \\ a = \frac{ – 5}{ – 2} \\ a = \boxed{ \frac{5}{2} } [/tex]
✯✯✯✯✯_________________________✯✯✯✯✯
[tex]\bold \star\red{\underline{\boxed{Hope \: it \: helps \: you}}}\star[/tex]
[tex]\bold \star\orange{\underline{\boxed{Pls \: follow \: kar \: do}}}\star[/tex]
[tex]\bold \star\red{\underline{\boxed{Pls \: mark \: me\: brainlist}}}\star[/tex]
✯✯✯✯✯_________________________✯✯✯✯✯