A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden. How much area will it cover in 8

2 thoughts on “A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden. How much area will it cover in 8”

1. Step-by-step explanation:

   correct answer

   211.2 of (a)

   528 of (b)

   25 of (c)

   4158 of (d)

   7 of (e)

   which one is easy you.

   The correct answer

   1.

   circumference of circle = 2pir

   = 2 x pi x 1.4

   = 8.81 m

   Area = length x breadth

   = 8.81 x 3

   = 26 .43 m^{2}

   Area cover in 8 revolutions = 26.43 x 8

   = 211.44 m^{2}————————————————————————2.

   Area of the canvas = Curved surface area of the conical tent

   Since the canvas is rectangular in shape, its area is = length × width

   Curved surface area of a cone =πrl, where r is the radius of the cone and l is the slant height.

   For \: a \: cone \: , l= \sqrt{h { }^{2} } + \sqrt{r {}^{2} }

   where l is the slant height.

   Hence, l= \sqrt{24 {}^{2} } + \sqrt{7 {}^{2} }

   ⇒l= \: \: \sqrt{625}

   ⇒l=25 cm

   Hence, length ×5= 22/7 ×7×25

   ∴ length =110 m————————————————————————3.Given :-

   The total surface area of a cone of radius 7 cm is 704 cm².

   To find :-

   The slant height.

   Solution :-

   Let the slant height of the cone is l cm.

   Radius = 7 cm

   According to the question,

   πr(r+l) = 704

   → (22/7) ×7 (7+l) = 704

   → 22(7+l) = 704

   → 7+l = 704/22

   → 7+l = 32

   → l = 32-7

   → l = 25

   Therefore, the slant height of the cone is 25 cm.————————————————————————4.

   Let r be the radius of the hemisphere.

   Given that, base area = πr2 = 1386 sq. m

   T.S.A. = 3πr2 sq.m

   = 3 ×1386 = 4158

   Therefore, T.S.A. of the hemispherical solid is 4158 m2————————————————————————5.

   d≈7

   ASurface area

   154

   Unit Conversion:

   Using the formulas

   A=4πr2

   d=2r

   Solving for d

   d=A

   π=154

   π≈7.00141————————————————————————

   Reply

2. Area covered = Curved surface × Number of revolutions

   r=21.4=0.7 m

   h=2 m

   Curved surface = 2πrh=2×722×0.7×2=8.8 m2

   Hence,

   Area covered = 8.8×5=44 m2

   Reply