father is 20 years older than his son, lf the sum of their age is 40 years. find their ages About the author Alice
Answer: Father: 30 Son: 10 Step-by-step explanation: Equation: If the son’s age is y, then, y + (y + 20) = 40 2y + 20 = 40 2y = 40 – 20 2y = 20 y = 20 / 2 y = 10 So the son’s age is 10. If the son’s age is 10, then, 10 + 20 = 30 Hence the father’s age is 30. Reply
Answer: Father = 30 years Son = 10 years Step-by-step explanation: Q. Father is 20 years older than son, sum of their ages is 40 years, so what are the ages of them. Solution – If we consider son’s age as x so father’s age will be x + 20 sum of both ages = 40 => x + x + 20 = 40 => 2x + 20 = 40 => 2x = 40–20 => 2×x = 20 => x = 20÷2 => x = 10 Hence son’s age = x = 10 years Father’s age = x + 20 = 10+20 = 30 years hope it helps. Reply
Answer:
Father: 30
Son: 10
Step-by-step explanation:
Equation:
If the son’s age is y, then,
y + (y + 20) = 40
2y + 20 = 40
2y = 40 – 20
2y = 20
y = 20 / 2
y = 10
So the son’s age is 10.
If the son’s age is 10, then,
10 + 20
= 30
Hence the father’s age is 30.
Answer:
Father = 30 years
Son = 10 years
Step-by-step explanation:
Q. Father is 20 years older than son, sum of their ages is 40 years, so what are the ages of them.
Solution –
If we consider son’s age as x
so father’s age will be x + 20
sum of both ages = 40
=> x + x + 20 = 40
=> 2x + 20 = 40
=> 2x = 40–20
=> 2×x = 20
=> x = 20÷2
=> x = 10
Hence son’s age = x = 10 years
Father’s age = x + 20 = 10+20 = 30 years
hope it helps.