If Alpha , ß be to root of the equationax² + bx + c = 0 and their ratio is 3:1then proved that 12b² = 49ac About the author Josephine
Step-by-step explanation: ax² + bx + c = 0 Sum of roots, s = -b/a Product of roots, p = c/a Given, α = 3k β = k Sum of roots, s = α+β = 4k Product of roots, p = αβ = 3k² So, -b/a = 4k ——-(1) c/a = 3k² k² = c/3a ——-(2) Squaring (1), b²/a² = 16k² k² = b²/16a² c/3a = b²/16a² b² = 16ac Reply
Step-by-step explanation:
ax² + bx + c = 0
Sum of roots, s = -b/a
Product of roots, p = c/a
Given,
α = 3k
β = k
Sum of roots, s = α+β = 4k
Product of roots, p = αβ = 3k²
So,
-b/a = 4k ——-(1)
c/a = 3k²
k² = c/3a ——-(2)
Squaring (1),
b²/a² = 16k²
k² = b²/16a²
c/3a = b²/16a²
b² = 16ac