If Alpha , ß be to root of the equation
ax² + bx + c = 0 and their ratio is 3:1
then proved that 12b² = 49ac​

If Alpha , ß be to root of the equation
ax² + bx + c = 0 and their ratio is 3:1
then proved that 12b² = 49ac​

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Josephine

1 thought on “<br />If Alpha , ß be to root of the equation<br />ax² + bx + c = 0 and their ratio is 3:1<br />then proved that 12b² = 49ac​”

  1. Step-by-step explanation:

    ax² + bx + c = 0

    Sum of roots, s = -b/a

    Product of roots, p = c/a

    Given,

    α = 3k

    β = k

    Sum of roots, s = α+β = 4k

    Product of roots, p = αβ = 3k²

    So,

    -b/a = 4k ——-(1)

    c/a = 3k²

    k² = c/3a ——-(2)

    Squaring (1),

    b²/a² = 16k²

    k² = b²/16a²

    c/3a = b²/16a²

    b² = 16ac

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