Find the perimeter of a triangle whose sides are 2a +3b,b-a, 4a-2b.

Question

Find the perimeter of a triangle whose sides are 2a +3b,b-a, 4a-2b.​

Mackenzie · Answer

Answer:   5a+b   Step-by-step explanation:   2a+3b,b-a,4a-3b.         perimeter = sum of all sides  =2a-a+4b+3b+b-3b  =5a+b  Hence, perimeter = 5a+b

Bella · Answer

Answer:   5a+2b   Step-by-step explanation:    The perimeter is the sum of the sides of the polygon.  Here, the sides are (2a+3b), (b-a) and (4a-2b).  Adding the sides:    (2a+3b)+(b-a)+(4a-2b)  2a+3b+b-a+4a-2b  2a-a+4a+3b+b-2b  2a+4a-a+3b+b-2b  5a+2b   So, the perimeter of this triangle is 5a+2b.     Hope this helps... Thank you for viewing my answer!

Daisy

Let’s learn.
In fig. 6.16, the perpendicular bisectors of
sides of A PQR are intersecting at point
C. So C is the p

(2) The cordinates of the origin are (1, 1 ) true or false

2 thoughts on “Find the perimeter of a triangle whose sides are 2a +3b,b-a, 4a-2b.”

So, the perimeter of this triangle is 5a+2b.

Leave a Comment Cancel reply