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In front of a 200 meters long wall, a triangular plot is to be cordoned off using the wall as one of its sides and a fencing of to

By Kylie

In front of a 200 meters long wall, a triangular plot is to be cordoned off using the wall as one of its sides and a fencing of total length 300 meters to form the other two sides. Then the maximum possible area (in square meters) of the plot that can be cordoned off is​

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Kylie

3. A sum of Rs 30,000 is invested for 3 years at 712% p.a. compound interest.
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1 thought on “In front of a 200 meters long wall, a triangular plot is to be cordoned off using the wall as one of its sides and a fencing of to”

  1. [tex]\huge\bf\underline{\red{A}\green{N}\orange{S}\pink{W}\purple{E}\blue{R}}[/tex]

    • For maximum area of a rt angled triangle with a fixed hypotenuse, base and height should be equal.
    • base = height = s

    then

    • s^2+s^2= 100^2
    • s^2= 0.5 *(100)^2

    => area of triangle = 1/2 *s*s = (1/4)*(100)^2= 50^2 = 2500 sq mtrs

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