perimeter of rectangle whose length is 20/3 and 9/2breath please tell the answer I want to check About the author Remi
Question:- What is the perimeter of the rectangle whose length is [tex] \frac{20}{3} [/tex]and breadth is [tex] \frac{9}{2} [/tex] Solution:- Given, Length of rectangle = [tex] \frac{20}{3} [/tex] Breadth of rectangle = [tex] \frac{9}{2} [/tex] We have, Perimeter of rectangle is 2(length+Breadth) So, Perimeter = [tex]2( \frac{20}{3} + \frac{9}{2} )[/tex] LCM = 2×3 = 6 So, [tex]2 \times ( \frac{20 \times 2}{3 \times 2} + \frac{9 \times 3}{2 \times 3} ) [/tex] [tex]2 \times ( \frac{40}{6} + \frac{27}{6} )[/tex] [tex]2 \times ( \frac{40 + 27}{6} )[/tex] [tex]2 \times ( \frac{67}{6} )[/tex] [tex] = > \frac{67}{3} [/tex] Perimeter of rectangle is [tex] \frac{67}{3} [/tex] cm Reply
Question:-
What is the perimeter of the rectangle whose length is [tex] \frac{20}{3} [/tex]and breadth is [tex] \frac{9}{2} [/tex]
Solution:-
Given,
Length of rectangle = [tex] \frac{20}{3} [/tex]
Breadth of rectangle = [tex] \frac{9}{2} [/tex]
We have,
Perimeter of rectangle is 2(length+Breadth)
So, Perimeter =
[tex]2( \frac{20}{3} + \frac{9}{2} )[/tex]
LCM = 2×3 = 6
So,
[tex]2 \times ( \frac{20 \times 2}{3 \times 2} + \frac{9 \times 3}{2 \times 3} ) [/tex]
[tex]2 \times ( \frac{40}{6} + \frac{27}{6} )[/tex]
[tex]2 \times ( \frac{40 + 27}{6} )[/tex]
[tex]2 \times ( \frac{67}{6} )[/tex]
[tex] = > \frac{67}{3} [/tex]
Perimeter of rectangle is [tex] \frac{67}{3} [/tex] cm
Answer:
Perimeter of a rectangle= 2(l+b)
So,
2(20/3 + 9/2)
2×67/6 = 67/2
So, answer is 67/2