The area of a sheet of 6237/ 10 sq. cm. If its length is 297 /10 cm , find its width .​

2 thoughts on “The area of a sheet of 6237/ 10 sq. cm. If its length is 297 /10 cm , find its width .​”

1. Question:

   The area of a sheet of 6237/ 10 sq. cm. If its length is 297 /10 cm , find its width .

   Answer:

   Area of rectangle = 6237/10 sq.cm

   l × b = 6237/10 sq.cm

   297/10 × b = 6237/10 sq.cm

   b = 6237/10 × 10/297

   b = 21 cm

   Therefore, width = 21 cm

   hope it helps you :–)

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2. Given:–

   •Area of a sheet is 6237/10 sq.cm.

   •Length of a sheet is 297/10 cm.

   To Find:–

   •Find its width.

   Solution:–

   Let consider Breadth of a sheet be x.

   we have,

   • Length = 297/10 cm
   • Area = 6237/10 sq.cm.

   Using Formula:

   [tex] \: \: \sf \: area \: of \: sheet = length \times breadth[/tex]

   Now substitute the values,

   [tex] \: \: \sf \: \frac{6237}{10} = \frac{297}{10} \times x \\ \\ \: \: \sf \: \frac{ \frac{6237}{10} }{ \frac{297}{10} } = x \\ \\ \: \: \sf \: x = \frac{6237}{1 \cancel0} \times \frac{1 \cancel0}{297} \\ \\ \: \: \sf \: x = 21[/tex]

   Henceforth,Breadth of a sheet is 21 cm.

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   Extra Info…

   • Perimeter of rectangle = 2(length + Breadth)
   • Length of a rectangle= Area/Breadth
   • Breadth of a rectangle= Area/Length
   • Diagonal of rectangle = √(Length)^2+(Breadth)^2

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