Given question -: if x-a is a factor of ( x³- ax²+ 2x +a-1), find the value of a let’s try to solve the question Given that x-a is a factor of [tex] {x}^{3} – a {x}^{2} + 2x + a – 1[/tex] so [tex]x – a = 0[/tex] [tex]x = a[/tex] Now put the value of x in above equation [tex] \implies \: {x}^{3} – {x}^{2} + 2x + a – 1 = 0[/tex] [tex] \implies \: {a}^{3} – (a) {a}^{2} + 2a + a – 1 = 0 [/tex] [tex] \implies \: {a}^{3} – {a}^{3} + 2a + a – 1 = 0[/tex] [tex] \implies \: 3a – 1 = 0[/tex] [tex] \implies \: a= \frac{1}{3} [/tex] Hope this will help you Thank you.. Reply
Given question -:
if x-a is a factor of ( x³- ax²+ 2x +a-1), find the value of a
let’s try to solve the question
Given that x-a is a factor of
[tex] {x}^{3} – a {x}^{2} + 2x + a – 1[/tex]
so
[tex]x – a = 0[/tex]
[tex]x = a[/tex]
Now put the value of x in above equation
[tex] \implies \: {x}^{3} – {x}^{2} + 2x + a – 1 = 0[/tex]
[tex] \implies \: {a}^{3} – (a) {a}^{2} + 2a + a – 1 = 0 [/tex]
[tex] \implies \: {a}^{3} – {a}^{3} + 2a + a – 1 = 0[/tex]
[tex] \implies \: 3a – 1 = 0[/tex]
[tex] \implies \: a= \frac{1}{3} [/tex]
Hope this will help you
Thank you..
Answer:
4 a
Step-by-step explanation:
I think it I don’t it is correct answer