Geometry: Triangleb) In the given figure, ZDEF = ZDHG = 50°. Prove that,(i) ADHG – ADEFDG GH(ii)EF50AHDFEA50°F About the author Hailey
Answer: For triangle DEF, let the angles are x,y and z then x+y+z=180o ∠DFP=180o−x ∠EDQ=180o−y ∠FER=180o−z Add these three equations, we get ∠DFP+∠EDQ+∠FER=540o−(x+y+z) =540o−180o =360o Hence, ∠DFP+∠EDQ+∠FER=360o Reply
Answer:
For triangle DEF, let the angles are x,y and z
then x+y+z=180o
∠DFP=180o−x
∠EDQ=180o−y
∠FER=180o−z
Add these three equations, we get
∠DFP+∠EDQ+∠FER=540o−(x+y+z)
=540o−180o
=360o
Hence, ∠DFP+∠EDQ+∠FER=360o