[tex]\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}[/tex] [tex]\boxed {x=-3}[/tex] [tex]\boxed {y=2}[/tex] [tex]\boxed {\underline {\mathbb {GIVEN:-}}}[/tex] [tex]2x+ y = -4\\x + y = -1[/tex] [tex]\boxed {\underline {\mathbb {TO\:FIND:-}}}[/tex] value of x and y [tex]\boxed {\underline {\mathbb {METHOD\:USED:-}}}[/tex] [tex]elimination \: method[/tex] [tex]\boxed {\underline {\mathbb {SOLUTION:-}}}[/tex] Let [tex]2x+y=-4…(1)[/tex] And [tex]x+y=-1…(2)[/tex] now by using eq2 let’s make eq3 we get- [tex]x+y=-1[/tex] [tex]x=-1-y[/tex] [ ← by bringing y to RHS] hence [tex]x=-1-y…(3)[/tex] now by using elimination method put eq3 in eq1 we get- [tex]2(-1-y)+y=-4[/tex] [ ←putted value in eq] [tex]-1 \times 2-y \times 2 + y =-4 \\-2-2y+y=-4\\-2-y=-4\\[/tex] [tex]-y=-4+2[/tex] [brought -2 to RHS get +2] [tex]-y=-2[/tex] [ ← when bring – to RHS we get – and – as +] [tex]\boxed {y=2}[/tex] as we get y value so let’s put in eq3 to get x value [tex]x=-1-(2)[/tex] [← putted y value in eq3] [tex]x=-1-2\\\boxed {x=-3}[/tex] ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ Reply
[tex]\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}[/tex] [tex]\boxed {x=-3}[/tex] [tex]\boxed {y=2}[/tex] [tex]\boxed {\underline {\mathbb {GIVEN:-}}}[/tex] [tex]2x+ y = -4\\x + y = -1[/tex] [tex]\boxed {\underline {\mathbb {TO\:FIND:-}}}[/tex] value of x and y [tex]\boxed {\underline {\mathbb {METHOD\:USED:-}}}[/tex] [tex]elimination \: method[/tex] [tex]\boxed {\underline {\mathbb {SOLUTION:-}}}[/tex] Let [tex]2x+y=-4…(1)[/tex] And [tex]x+y=-1…(2)[/tex] now by using eq2 let’s make eq3 we get- [tex]x+y=-1[/tex] [tex]x=-1-y[/tex] [ ← by bringing y to RHS] hence [tex]x=-1-y…(3)[/tex] now by using elimination method put eq3 in eq1 we get- [tex]2(-1-y)+y=-4[/tex] [ ←putted value in eq] [tex]-1 \times 2-y \times 2 + y =-4 \\-2-2y+y=-4\\-2-y=-4\\[/tex] [tex]-y=-4+2[/tex] [brought -2 to RHS get +2] [tex]-y=-2[/tex] [ ← when bring – to RHS we get – and – as +] [tex]\boxed {y=2}[/tex] as we get y value so let’s put in eq3 to get x value [tex]x=-1-(2)[/tex] [← putted y value in eq3] [tex]x=-1-2\\\boxed {x=-3}[/tex] ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ Reply
[tex]\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}[/tex]
[tex]\boxed {x=-3}[/tex]
[tex]\boxed {y=2}[/tex]
[tex]\boxed {\underline {\mathbb {GIVEN:-}}}[/tex]
[tex]2x+ y = -4\\x + y = -1[/tex]
[tex]\boxed {\underline {\mathbb {TO\:FIND:-}}}[/tex]
value of x and y
[tex]\boxed {\underline {\mathbb {METHOD\:USED:-}}}[/tex]
[tex]elimination \: method[/tex]
[tex]\boxed {\underline {\mathbb {SOLUTION:-}}}[/tex]
Let [tex]2x+y=-4…(1)[/tex]
And
[tex]x+y=-1…(2)[/tex]
now by using eq2 let’s make eq3
we get-
[tex]x+y=-1[/tex]
[tex]x=-1-y[/tex] [ ← by bringing y to RHS]
hence [tex]x=-1-y…(3)[/tex]
now by using elimination method put eq3 in eq1
we get-
[tex]2(-1-y)+y=-4[/tex] [ ←putted value in eq]
[tex]-1 \times 2-y \times 2 + y =-4 \\-2-2y+y=-4\\-2-y=-4\\[/tex]
[tex]-y=-4+2[/tex] [brought -2 to RHS get +2]
[tex]-y=-2[/tex] [ ← when bring – to RHS we get – and – as +]
[tex]\boxed {y=2}[/tex]
as we get y value so let’s put in eq3 to get x value
[tex]x=-1-(2)[/tex] [← putted y value in eq3]
[tex]x=-1-2\\\boxed {x=-3}[/tex]
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[tex]\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}[/tex]
[tex]\boxed {x=-3}[/tex]
[tex]\boxed {y=2}[/tex]
[tex]\boxed {\underline {\mathbb {GIVEN:-}}}[/tex]
[tex]2x+ y = -4\\x + y = -1[/tex]
[tex]\boxed {\underline {\mathbb {TO\:FIND:-}}}[/tex]
value of x and y
[tex]\boxed {\underline {\mathbb {METHOD\:USED:-}}}[/tex]
[tex]elimination \: method[/tex]
[tex]\boxed {\underline {\mathbb {SOLUTION:-}}}[/tex]
Let [tex]2x+y=-4…(1)[/tex]
And
[tex]x+y=-1…(2)[/tex]
now by using eq2 let’s make eq3
we get-
[tex]x+y=-1[/tex]
[tex]x=-1-y[/tex] [ ← by bringing y to RHS]
hence [tex]x=-1-y…(3)[/tex]
now by using elimination method put eq3 in eq1
we get-
[tex]2(-1-y)+y=-4[/tex] [ ←putted value in eq]
[tex]-1 \times 2-y \times 2 + y =-4 \\-2-2y+y=-4\\-2-y=-4\\[/tex]
[tex]-y=-4+2[/tex] [brought -2 to RHS get +2]
[tex]-y=-2[/tex] [ ← when bring – to RHS we get – and – as +]
[tex]\boxed {y=2}[/tex]
as we get y value so let’s put in eq3 to get x value
[tex]x=-1-(2)[/tex] [← putted y value in eq3]
[tex]x=-1-2\\\boxed {x=-3}[/tex]
⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔