Areas of triangles are in the ratio 81:16 but the sides of two similar triangle is About the author Kennedy
Step-by-step explanation: 16:11 Let us have two similar triangles ΔABC and ΔDEF as shown below. As they are similar, we have ABDE=ACDF=BCEF Let us also draw perpendiculars AP and DQ from A and D respectively on to BC and EF as shown.  It is apparent that ΔAPB and ΔDEQ are also similar as all respective angles are equal. Hence, ABDE=APDQ=BPEQ We also have ΔABC=12×BC×AP and ΔDEF=12×EF×DQ and ΔAPBΔDEQ=BC×APEF×DQ=BCEF×APDQ But APDQ=ABDE Reply
Step-by-step explanation:
16:11
Let us have two similar triangles ΔABC and ΔDEF as shown below. As they are similar, we have
ABDE=ACDF=BCEF
Let us also draw perpendiculars AP and DQ from A and D respectively on to BC and EF as shown.

It is apparent that ΔAPB and ΔDEQ are also similar as all respective angles are equal. Hence,
ABDE=APDQ=BPEQ
We also have ΔABC=12×BC×AP and ΔDEF=12×EF×DQ and
ΔAPBΔDEQ=BC×APEF×DQ=BCEF×APDQ
But APDQ=ABDE