The length of a rectangle is 3 yds longer than its width.
If the perimeter of the rectangle is 70 yds, find its length and w

1 thought on “The length of a rectangle is 3 yds longer than its width.<br /> If the perimeter of the rectangle is 70 yds, find its length and w”

1. Given

   • Length of rectangle=3 yds more than Breadth
   • Perimeter of Rectangle=70 yds

   To Find

   • Length and Breadth

   Solution

   Let Breadth be x

   .°. Length of rectangle=3+x

   We know that

   [tex] \boxed{\bf{Perimeter\ of\ rectangle= 2(length+Breadth}}[/tex]

   [tex]\sf\dashrightarrow{70= 2(3 + x + x)}[/tex]

   [tex]\sf\dashrightarrow{2 x + 3= 35}[/tex]

   [tex]\sf\dashrightarrow{2 x = 35 – 3}[/tex]

   [tex]\sf\dashrightarrow{2 x = 32}[/tex]

   [tex]\bf\dashrightarrow{x = 16}[/tex]

   • Breadth of rectangle=16 yds.
   • Length of rectangle= 19 yds.

   [tex]\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{perimeter \: of \: rectangle = 2(l + b)}} \\ \\ \dashrightarrow \sf{area \: of \: rectangle = length \: \times breadth }\\ \\ \dashrightarrow \sf{perimeter \: of \: square = 4 \times side } \\ \\ \dashrightarrow \sf{area \: of \: square =(side) ^{2} } \\ \\ \dashrightarrow \sf{area \: of \: parallelogram = base \times height} \\ \\ \dashrightarrow \sf{area \: of \: trapezium = \frac{1}{2}sum \: of \: parallel \: de \: \times \: height }\\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}[/tex]

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