Difference between 2 numbers is 30. Twice
the greater number is less than 7 times the
smaller number by 5 . Find the num

Difference between 2 numbers is 30. Twice
the greater number is less than 7 times the
smaller number by 5 . Find the numbers.​

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  1. Answer:

    let x and y be two numbers

    x-y = 30

    then x = 30+y

    according to problem,

    2x = 7y-5

    2(30+y) = 7y -5

    60+2y = 7y-5

    60+5 = 7y-2y

    65 = 5y

    y= 65/5

    y= 13

    therefore smallest number y is 13

    and the largest number x is 30 + 13 = 43

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