Difference between 2 numbers is 30. Twicethe greater number is less than 7 times thesmaller number by 5 . Find the numbers. About the author Bella
Answer: let x and y be two numbers x-y = 30 then x = 30+y according to problem, 2x = 7y-5 2(30+y) = 7y -5 60+2y = 7y-5 60+5 = 7y-2y 65 = 5y y= 65/5 y= 13 therefore smallest number y is 13 and the largest number x is 30 + 13 = 43 Reply
Answer:
let x and y be two numbers
x-y = 30
then x = 30+y
according to problem,
2x = 7y-5
2(30+y) = 7y -5
60+2y = 7y-5
60+5 = 7y-2y
65 = 5y
y= 65/5
y= 13
therefore smallest number y is 13
and the largest number x is 30 + 13 = 43