Answer: Correct option is B 3 2 , 7 −1 Given quadratic polynomial is 7y 2 − 3 11 y− 3 2 . = 3 1 (21y 2 −11y−2) = 3 1 (21y 2 −14y+3y−2) = 3 1 [7y(3y−2)+(3y−2)] = 3 1 (3y−2)(7y+1) y= 3 2 , y=− 7 1 The zeroes of the polynomials are, 3 2 , − 7 1 Relationship between the zeroes and the coefficients of the polynomials- Sum of the zeros=- coefficient of y 2 coefficient of y =− ⎝ ⎜ ⎜ ⎜ ⎛ 7 − 3 11 ⎠ ⎟ ⎟ ⎟ ⎞ = 21 11 Also sum of zeroes= 3 2 +(− 7 1 ) = 21 14−3 = 21 11 Product of the zeroes = coefficient of y 2 constant term = 7 − 3 2 = 21 −2 Also the product of the zeroes= 3 2 ×(− 7 1 )= 21 −2 Hence verified. Option B is correct Reply
Answer:
Correct option is
B
3
2
,
7
−1
Given quadratic polynomial is 7y
2
−
3
11
y−
3
2
.
=
3
1
(21y
2
−11y−2)
=
3
1
(21y
2
−14y+3y−2)
=
3
1
[7y(3y−2)+(3y−2)]
=
3
1
(3y−2)(7y+1)
y=
3
2
, y=−
7
1
The zeroes of the polynomials are,
3
2
, −
7
1
Relationship between the zeroes and the coefficients of the polynomials-
Sum of the zeros=-
coefficient of y
2
coefficient of y
=−
⎝
⎜
⎜
⎜
⎛
7
−
3
11
⎠
⎟
⎟
⎟
⎞
=
21
11
Also sum of zeroes=
3
2
+(−
7
1
)
=
21
14−3
=
21
11
Product of the zeroes =
coefficient of y
2
constant term
=
7
−
3
2
=
21
−2
Also the product of the zeroes=
3
2
×(−
7
1
)=
21
−2
Hence verified.
Option B is correct